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A block of mass m is moving with a cons...

A block of mass m is moving with a constant acceleration a on a rough horizontal plane. If the coefficient of friction between the block and ground is `mu`, the power delivered by the external agent in a time interval t from the beginning is equal to:

A

`ma^(2)y`

B

`mu` mgat

C

`mu m ( a+ mu g)` gt

D

`m(a + mu g) `at

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step-by-step, we will analyze the forces acting on the block and calculate the power delivered by the external agent. ### Step 1: Identify the forces acting on the block The block of mass \( m \) is moving on a rough horizontal plane with a constant acceleration \( a \). The forces acting on the block include: - The external force \( F \) applied by the agent. - The frictional force \( f \) opposing the motion, which can be calculated using the coefficient of friction \( \mu \) and the normal force (which is equal to \( mg \) for horizontal motion). ### Step 2: Write the equation of motion Using Newton's second law, the net force acting on the block can be expressed as: \[ F - f = ma \] Where \( f = \mu mg \) (the frictional force). Therefore, we can rewrite the equation as: \[ F - \mu mg = ma \] ### Step 3: Solve for the external force \( F \) Rearranging the equation gives: \[ F = ma + \mu mg \] Factoring out \( m \) from the right-hand side: \[ F = m(a + \mu g) \] ### Step 4: Determine the velocity of the block after time \( t \) Using the kinematic equation for velocity: \[ V = U + at \] Assuming the initial velocity \( U = 0 \) (the block starts from rest), we have: \[ V = at \] ### Step 5: Calculate the power delivered by the external agent Power \( P \) delivered by the external force is given by the product of the force and the velocity: \[ P = F \cdot V \] Substituting the expressions for \( F \) and \( V \): \[ P = (m(a + \mu g))(at) \] This simplifies to: \[ P = m(at)(a + \mu g) \] Thus, the final expression for the power delivered by the external agent is: \[ P = m(at)(a + \mu g) \] ### Final Answer The power delivered by the external agent in a time interval \( t \) is: \[ P = m(at)(a + \mu g) \] ---

To solve the problem step-by-step, we will analyze the forces acting on the block and calculate the power delivered by the external agent. ### Step 1: Identify the forces acting on the block The block of mass \( m \) is moving on a rough horizontal plane with a constant acceleration \( a \). The forces acting on the block include: - The external force \( F \) applied by the agent. - The frictional force \( f \) opposing the motion, which can be calculated using the coefficient of friction \( \mu \) and the normal force (which is equal to \( mg \) for horizontal motion). ### Step 2: Write the equation of motion ...
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