A particle moves from position vector `r→1=(23Iˆ+2jˆ−6kˆ)` to position vector, `r→−2=(14Iˆ+13jˆ+9kˆ)` in metre under the action of a constant force of `F→`=`(14iˆ+jˆ+3kˆ)`N. Calculat word done by the force

Explanation

To calculate the work done by the force on the particle moving from position vector \( \vec{r_1} = 23\hat{i} + 2\hat{j} - 6\hat{k} \) to position vector \( \vec{r_2} = 14\hat{i} + 13\hat{j} + 9\hat{k} \) under the action of a constant force \( \vec{F} = 14\hat{i} + \hat{j} + 3\hat{k} \), we can follow these steps:

### Step 1: Calculate the Displacement Vector
The displacement vector \( \vec{s} \) is given by the difference between the final position vector \( \vec{r_2} \) and the initial position vector \( \vec{r_1} \):

\[ \vec{s} = \vec{r_2} - \vec{r_1} \]
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