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A block of mass m=0.1kg is released from...

A block of mass `m=0.1kg` is released from a height of 4 m on a curved smooth surface. On the horizonal surface, path AB is smooth and path BC is rough with a coefficient of friction `mu=0.1`. If the impact of the block with the verical wall at C is perfectly elastic, the total distance covered by the block on the horizontal surface before coming to rest will be (take `g=10ms^(-2)`)

Text Solution

Verified by Experts

KE attained by block at `B=mgh=4J`
Work done by friction force on path `BC=(-mu mg)(BC)=-0.2J`
On the other horizontal surface block can make total forward and backward `((4)/(0.2))=20` trips.
But last time it will stop at B
`:.` Distance covered `=20xx(AB+BC)-AB=59m`.
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