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A particle of mass m is released from th...

A particle of mass m is released from the edge of a rough bowl of radius r. It momentrially comes to rest at point B, whose radius vector making an angle `30^(@)` with the vertical . If `mu=(1)/(sqrt(3))`, then work done by the frictional force on the particle is

A

`-(mu m gR)/(2)`

B

`(mgR)/(2)`

C

`-(sqrt(3)mu m gR)/(2)`

D

`-(sqrt(3)mgR)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
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