Two immiscible of densities `2.5g//cm^(3)` and `0.8g//cm^(3)` are taken in the ratio of their masses as `2:3` respectively find the average density of the liquid conbination.

Explanation

Let the masses be . 2m . and . 3m. gm respectively . Therefore the volume of the first liquid of density `2.5 gm//cm^(3) ` is `V_(1) = (2m)/(2.5) cm^(3)`
That of tha second liquid is `V_(2) = (3m)/(0.8) cm^(3)`
Total volume `V=V_(1)+V_(2)=(2m)/(2.5) + (3m)/(0.8) cm^(3)`
Total mass ` = 2m + 3m = 5m ` gm
Therefore, the average density
`rho_(av) = (5m)/V = (5m)/((2m)/(2.5)+(3m)/(0.8))cm^(3) = 1.09 gm//cm^(3)`