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A metal plate 0.04m^(2) in area is lying...

A metal plate `0.04m^(2)` in area is lying on a liquid layer of thickness `10^(-3)m` and coefficient of viscosity 140 poise. Calculate the horizontal force needed to move the plate with a speed of 0.040 m/s.

Text Solution

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Area of the place ` A = 0.04 m^(2)`
Thickness `Deltax = 10^(-3) m `
`Deltax` is the distance of the free surface with respect to the fixed surface.
Velocity gradient , `(Deltav)/(Deltax) = (0.04 m//s)/(10^(-3)m) = 40 s^(-1)`
Coefficient of viscosity ` eta = 14 kg//ms^(-1)`
Let F be the required force ,
Then , `F = eta A = (Deltav)/(Deltax) = 22.4 N `
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