Two long capillary tubes of diameter ` 5.0` mm and `4.0 ` mm are held vertically inside water one by one . How much high the water will rise in each tube ? ( `g = 10 m//s^(2)` , surface tension of water ` = 7.0 xx 10^(-2)` N/m)

Explanation

To solve the problem of how high water will rise in two capillary tubes of different diameters, we can use the formula for the height of liquid rise in a capillary tube, which is given by:

\[ h = \frac{2T \cos \theta}{\rho g r} \]

Where:
- \( h \) = height of the liquid column
- \( T \) = surface tension of the liquid (water in this case)
- \( \theta \) = contact angle (for water in a clean glass tube, it is approximately 0 degrees, so \( \cos \theta = 1 \))
...