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The excess pressure inside one soap bubb...

The excess pressure inside one soap bubble is four times that of other. Then the ratio of volume of the first bubble to other is

A

` 1:64`

B

`1:4`

C

`64:1`

D

`1:2`

Text Solution

Verified by Experts

`(P_(1))/(P_(2)) = 4 ` or `P_(1) = 4P_(2)`
` (4T)/(r_(1)) = (4 xx 4T)/(r_(2)) rArr (r_(1))/(r_(2)) = 1/4`
` (V_(1))/(V_(2)) = (r_(1)^(3))/(r_(2)^(3)) = (1/4)^(3) = 1/64`
Hence ( A ) is correct
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