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An air bubble of diameter 2mm rises stea...

An air bubble of diameter `2mm` rises steadily through a solution of density `1750kgm^(-3)` at the rate of `0.35cms^(-1)` .Calculate the coefficient of viscosity of the solution (in `Pascal times Sec`).The density of air is negligible. `(g=9.8m/s^(2))`

A

9 poise

B

6 poise

C

11 poise

D

4 poise

Text Solution

AI Generated Solution

To calculate the coefficient of viscosity of the solution, we can use the balance of forces acting on the air bubble as it rises through the liquid. The buoyant force acting on the bubble is equal to the viscous force acting against it when the bubble rises at a constant velocity. ### Step-by-Step Solution: 1. **Identify the Given Values:** - Diameter of the air bubble, \(d = 2 \, \text{mm} = 2 \times 10^{-3} \, \text{m}\) - Radius of the air bubble, \(r = \frac{d}{2} = 1 \times 10^{-3} \, \text{m}\) - Density of the solution, \(\rho = 1750 \, \text{kg/m}^3\) ...
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