Home
Class 12
PHYSICS
A rubber ball of mass 10 gram and volume...

A rubber ball of mass 10 gram and volume `15 cm^3` is dipped in water to a depth of 10m. Assuming density of water uniform throughout the depth, find the acceleration of the ball `("Take g" =980 cm//s^2)`

Text Solution

Verified by Experts

(a) `4.9 m//s^(2)` (b) ` 2.02 ` sec
Promotional Banner

Similar Questions

Explore conceptually related problems

A rubber ball floats on water with its 1/3 rd volume outside water. What is the density of rubber?

If pressure at the half depth of a lake is equal to 3/4 times the pressure at its bottom, then find the depth of the lake. [Take g = 10 m/ s^(2) ]

One end of a glass capillary tube with a radius r=0.05cm is immersed into water to a depth of h=2cm .Excess pressure required to blow an air bubble out of the lower end of the tube will be (S.T of water =70"dyne"//cm ).Take g=980cm//s^(2) .

When a glass capillary tube of radius 0.015 cm is dipped in water, the water rises to a height of 15 cm within it. Assuming contact angle between water and glass to be 0°, the surface tension of water.is [pwaler = 1000 kg m^(-3) , g = 9.81 m s^^(-2) ]

A cylindrical tub of radius 12 cm contains water to a depth of 20 cm. A spherical ball is dropped into the tub and the level of the water is raised by 6.75 cm. Find the radius of the ball.

A cylindrical tub of radius 12 cm contains water to a depth of 20 cm. A spherical ball is dropped into the tub and the level of the water is raised by 6.75 cm. Find the radius of the ball.

A rubber ball floats on water with its 1//3^(rd) volume outside water. What is the density of rubber?

A wooden ball of density D is immersed in water of density d to a depth h//2 below the surface of water and then relased. To what height will the ball jump out of water ?

A ball is thrown up at a speed of 4.0 m/s. Find the maximum height reached by the ball. Take g=10 m//s^2 .

A ball of mass 5.0 gm and relative density 0.5 strikes the surface of the water with a velocity of 20 m/sec. It comes to rest at a depth of 2m. Find the work done by the resisting force in water: (take g = 10 m//s^(2) )