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An ice cube floats in water. What percen...

An ice cube floats in water. What percentage of volume is outside water. Density of water `= 1g// c c`, density of ice `= 0.9 g// c c`.

A

`0.04`

B

`0.4`

C

`0.96`

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of determining the percentage of the volume of an ice cube that is outside of water when it floats, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Data:** - Density of water, \( \rho_w = 1 \, \text{g/cm}^3 \) - Density of ice, \( \rho_i = 0.9 \, \text{g/cm}^3 \) - Let the total volume of the ice cube be \( V \). 2. **Understand the Concept of Buoyancy:** - When an object floats, the weight of the object is equal to the buoyant force acting on it. - The buoyant force is equal to the weight of the water displaced by the submerged part of the ice cube. 3. **Set Up the Equations:** - The weight of the ice cube is given by: \[ \text{Weight of ice} = V \cdot \rho_i \cdot g \] - The buoyant force acting on the ice cube is given by: \[ \text{Buoyant force} = V' \cdot \rho_w \cdot g \] where \( V' \) is the volume of the ice cube that is submerged in water. 4. **Apply the Principle of Equilibrium:** - At equilibrium, the weight of the ice cube equals the buoyant force: \[ V \cdot \rho_i \cdot g = V' \cdot \rho_w \cdot g \] - We can cancel \( g \) from both sides: \[ V \cdot \rho_i = V' \cdot \rho_w \] 5. **Express the Submerged Volume:** - Rearranging the equation gives: \[ V' = \frac{V \cdot \rho_i}{\rho_w} \] - Substituting the values of densities: \[ V' = \frac{V \cdot 0.9}{1} = 0.9V \] 6. **Calculate the Volume Outside Water:** - The volume of the ice cube that is outside the water is: \[ V_{\text{outside}} = V - V' = V - 0.9V = 0.1V \] 7. **Determine the Percentage of Volume Outside Water:** - The percentage of the volume outside the water is given by: \[ \text{Percentage outside} = \left( \frac{V_{\text{outside}}}{V} \right) \times 100 = \left( \frac{0.1V}{V} \right) \times 100 = 10\% \] ### Final Answer: The percentage of the volume of the ice cube that is outside of the water is **10%**.
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