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Jupiter has a mass 318 times that of ear...

Jupiter has a mass 318 times that of earth, and its radius is 11.2 times the earth's radius Estimate the escape velocity of a body from Jupiter's surface, given that the escape velocity from the earth's surface `11.2 kms^(-1)`.

Text Solution

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Hence, `M_(J)=318M_(e )`, `R_(J)=11.2R_(e )`, `V_(e )=11.2 km//s`
We know, `v_(J)=sqrt((2GM_(J))/(R_(J)))` and `v_(e )=sqrt((GM_(e ))/(R_(e )))`
`:. (v_(J))/(v_(e ))=sqrt((M_(J))/(M_(e ))xx(R_(e ))/(R_(J)))`
`impliesv_(J)=v_(e )sqrt((M_(J))/(M_(e ))xx(R_(e ))/(R_(J)))`
`v_(J)=11.2{((318M_(e )))/M_(e )xx(R_(e ))/((11.2R_(e )))}^((1)/(2))=11.2((318)/(11.2))^((1)/(2))=59.7km//s`
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