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A particle hanging from a spring stretch...

A particle hanging from a spring stretches it by `1cm` at earth's surface. Radius of earth is `6400 km`. At a place `800 km` above the earth 's surface , the same particle will stretch the spring by

A

`1cm`

B

`8cm`

C

`0.1cm`

D

`0.79cm`

Text Solution

Verified by Experts

The correct Answer is:
D
`(kx_(1))/(kx_(2))=(F_(gr_(1)))/(F_(gr_(2)))=((r_(2))/(r_(1)))^(2)`
`implies(x_(1))/(x_(2))=((800+6400)/(6400))^(2)=((72)/(64))^(2)=((9)/(8))^(2)`
`implies(x_(1))/(x_(2))=(81)/(64)`
`impliesx_(2)=(64)/(81)x_(1)=(64)/(81)cm=0.79cm`
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