Home
Class 12
PHYSICS
The ratio of earth's orbital angular mom...

The ratio of earth's orbital angular momentum (about the sun ) to its mass is `4.4xx10^(15) m^(2)//s`. The area enclosed by earth's orbit approximately is (in `m^(2)`)

A

`7xx10^(22)m^(2)`

B

`6.02xx10^(23)m^(2)`

C

`7xx10^(23)m^(2)`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
`(L)/(M_(e ))=4.4xx10^(15)`
`implies(M_(e )vr)/(M_(e ))=4.4xx10^(15)` …………`(1)`
`(GMm)/(r^(2))=(mv^(2))/(r )impliesGM=v^(2)r`
`implies((2pir)/(365xx24xx60xx60))r=4.4xx10^(15)`
`impliespir^(2)~~7xx10^(22)m^(2)`
Promotional Banner

Similar Questions

Explore conceptually related problems

The ratio of earth.s orbital angular momentum (about the Sun) to its mass is 4.4 xx 10^(15) m^(2)s^(-1). Find the area enclosed by earth.s orbit.

The ratio of the earth's orbital angular momentum (about the Sun) to its mass is 4.4 xx 10^(15) m^(2) s^(-1) . The area enclosed by the earth's orbit is approximately-___________m^(2).

The orbital angular momentum of an electron in 2s -orbital is

The orbital angular momentum of an electron in 2s -orbital is

The orbital angular momentum of an electron in 2s orbital is ………

The orbital angular momentum of electron in 4s orbital of H atom is ……….

The orbital angular momentum of an electron of an electron in 2s orbitals is

A planet revolves about the sun in an elliptical orbit of semi-major axis 2xx10^(12) m . The areal velocity of the planet when it is nearest to the sun is 4.4xx10^(16) m//s . The least distance between the planet and the sun is 1.8xx10^(12) m//s . The minimum speed of the planet in km//s is 10 K . determine the value of K .

The mean radius of the earth's orbit round the sun is 1.5xx10^(11) . The mean radius of the orbit of mercury round the sun is 6xx10^(10)m . The mercury will rotate around the sun in

A planet revolves about the sun in elliptical orbit. The arial velocity ((dA)/(dt)) of the planet is 4.0xx10^(16) m^(2)//s . The least distance between planet and the sun is 2xx10^(12) m . Then the maximum speed of the planet in km//s is -