Home
Class 12
PHYSICS
A system consists of a thin charged wire...

A system consists of a thin charged wire ring of radius r and a very long uniformly charged wire oriented along the axis of the ring, with one of its ends coinciding with the center of the ring. The total charge on the ring is q. and he linear charge density on the straight wire is `lambda`, The interaction force between the ring and the wire is

Text Solution

Verified by Experts

The force of interaction due to ring on the element `dx` is
`dF=(GM(dm))/((r^(2)+x^(2)))cosalpha` where, `cosalpha=(x)/(sqrt(x^(2)+r^(2)))`
`impliesdF=(Gmxlambdadx)/((r^(2)+x^(2))^(3//2))`
`impliesF=Gmlambda int_(0)^(oo)(x dx)/((r^(2)+x^(2))^(3//2))=GMlambda int_(0)^(pi//2)(r^(2)tan theta sec^(2) theta d theta)/(r^(3) sec^(3) theta)`
`=(GMlambda)/(r )int_(0)^(pi//2)sin thetad theta=(GMlambda)/(r )|-costheta|_(0)^(pi//2)=(GMlambda)/(r )`
Promotional Banner

Similar Questions

Explore conceptually related problems

A system consits fo a thin charged wire ring of radius R and a very long uniformly charged thread oriented along the axis of the ring, with one of its ends coinciding with the centre of the ring. The total charge of the ring, with one of the ring so equal to q . The charge of the thread (per unit length) is equal to lambda . Find the interaction froce between the ring and the thread.

A very long uniformly charged wire oriented along the axis of a circular ring of radius R rests on its centre with one of the ends (as shown in figure). The linear charge density on the wire is lambda . Evalute the flux of the vector vecE across the circle area.

If linear charge density of a wire as shown in the figure is lambda

A thin circular wire of radius r has a charge Q. If a point charge q is placed at the centre of the ring, then find the increase in tension in the wire.

Electric charge Q is uniformly distributed around a thin ring of radius a. find the potential a point P on the axis of the ring at a distance x from the centre of the ring .

A half ring of radius r has a linear charge density lambda .The potential at the centre of the half ring is

Find the electric field at the centre of a uniformly charged semicircular ring of radius R. Linear charge density is lamda

A ring of radius R carries a non - uniform charge of linear density lambda = lambda_(0)costheta sec in the figure) Magnitude of the net dipolement of the ring is :

Charge q is uniformly distributed over a thin half ring of radius R . The electric field at the centre of the ring is

Two thin rings each of radius R are placed at a distance 'd' apart. The charges on the rings are +q and -q. The potential difference between their centres will be -