Escape velocity from the surface of moon is less than that from the surface of earth because the moon has no atmosphere while earth has a very dense one.

The escape velocity of a particle of a particle from the surface of the earth is given by

The acceleration due to gravity on the surface of the moon is (1)/(6)th of that on the surface of earth and the diameter of the moon is one-fourth that of earth. The ratio of escape velocities on earth and moon will be

The acceleration due to gravity on the surface of the moon is (1)/(6)th of that on the surface of earth and the diameter of the moon is one-fourth that of earth. The ratio of escape velocities on earth and moon will be

The escape velocity of a body from the surface of the earth is equal to

The escape velocity from the surface of the earth is (where R_(E) is the radius of the earth )

The value of escape speed from the surface of earth is

The escape velocity from the surface of the earth is V_(e) . The escape velcotiy from the surface of a planet whose mass and radius are three times those of the earth, will be

A particle is given a velocity (v_(e ))/(sqrt(3)) in a vertically upward direction from the surface of the earth, where v_(e ) is the escape velocity from the surface of the earth. Let the radius of the earth be R. The height of the particle above the surface of the earth at the instant it comes to rest is :

Two escape speed from the surface of earth is V_(e) . The escape speed from the surface of a planet whose mass and radius are double that of earth will be.

A rocket has to be launched from earh in such a way that it never returns. If E is the minimum energy delivered by the rocket launcher what should be the minimum energy that the launcher should have if the same rocket has launcher from the surface of the moon ? Assume that the density of the earth and the moon are equal and that the earth's volume is 64 times the volume of the moon