A thin hollow sphere of mass `m = 2kg`, `radius = (1//2) m` is sliding on a horizontal surface with a constant frequency n = 60 rpm. Find the total mechanical energy of the hollow sphere.

Explanation

To find the total mechanical energy of a thin hollow sphere sliding on a horizontal surface, we will consider both its translational and rotational kinetic energy. Here’s the step-by-step solution:

### Step 1: Convert the frequency to angular velocity
The frequency \( n \) is given as 60 revolutions per minute (rpm). We need to convert this to radians per second.

\[ \omega = n \times \frac{2\pi \text{ radians}}{1 \text{ revolution}} \times \frac{1 \text{ minute}}{60 \text{ seconds}} \]
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