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Two identical sonometer wires have a fundamental frequency of `500 Hz` when kept under the same tension . The percentage change in tension of one of the wires that would cause an occurrence of `5 beats//s` , when both wires vibrate together is

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To solve the problem, we need to determine the percentage change in tension of one of the sonometer wires that would result in a beat frequency of 5 beats per second when both wires are vibrating together. ### Step-by-Step Solution: 1. **Understanding the Frequency Relation**: The frequency of a vibrating wire is given by the formula: \[ f \propto \sqrt{T} ...
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