Two waves represented by `y_1=10 sin (2000 pi t)` and `y_2=10 sin (2000 pi t + pi//2)` superposed at any point at a particular instant. The resultant amplitude is

Options

A. 10 units
B. 20 units
C. 14.1 units
D. zero

Explanation

To find the resultant amplitude of the two waves given by \( y_1 = 10 \sin(2000 \pi t) \) and \( y_2 = 10 \sin(2000 \pi t + \frac{\pi}{2}) \), we can follow these steps:

### Step 1: Identify the Amplitudes and Phases
The first wave \( y_1 \) has an amplitude of \( A_1 = 10 \) and a phase of \( \phi_1 = 0 \). The second wave \( y_2 \) has an amplitude of \( A_2 = 10 \) and a phase of \( \phi_2 = \frac{\pi}{2} \).

### Step 2: Represent the Waves as Phasors
We can represent these waves as phasors in the complex plane:
- The phasor for \( y_1 \) is \( 10 \angle 0^\circ \) (along the positive x-axis).
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