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In an organ pipe (may be closed or open ...

In an organ pipe (may be closed or open ) of `99 cm` length standing wave is set up , whose equation is given by longitudinal displacement.

`xi = (0.1 mm) cos ( 2pi)/(0.8) (y + 1 cm) cos (400) t`where `y` is measured from the top of the tube in `metres` and `t "in" seconds` . Here `1 cm` is the end correction.
The upper end and the lower end of the tube are respectively .

A

First overtone

B

fifth harmonic

C

third harmonic

D

Fundamental mode

Text Solution

Verified by Experts

`(2pi)/0.8 =(2pi)/lambda` So `lambda=0.8` and effective length of air column = 0.99+0.01 = 1m
So `l/lambda=5/4 rArr l=5 lambda/4`, so five half loops will be formed
`l=5(lambda/4)` so second overtone
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