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Transverse wave is described by the equa...

Transverse wave is described by the equation `y=y_0 sin 2pi (ft-x/lambda)` .The maximum particle velocity is twice the wave velocity if wavelength is____

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To solve the problem, we need to analyze the relationship between the maximum particle velocity and the wave velocity for a transverse wave described by the equation \( y = y_0 \sin(2\pi(ft - \frac{x}{\lambda})) \). ### Step-by-Step Solution: 1. **Identify the Given Information**: - The wave equation is \( y = y_0 \sin(2\pi(ft - \frac{x}{\lambda})) \). - We need to find the wavelength \( \lambda \) when the maximum particle velocity is twice the wave velocity. ...
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