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Which of the following is a wave equatio...

Which of the following is a wave equation?

A

`y=Asink(x^(2)-vt^(2))`

B

`y=Acos2pi(x//lamda-t)`

C

`y=Asin2pi(x/lamda-t/T)`

D

`y=Asinkxcosomegat`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given options is a wave equation, we first need to understand the standard form of a wave equation. The most common form of a wave equation is given by: \[ y = A \sin(kx - \omega t) \] Where: - \( A \) is the amplitude of the wave, - \( k \) is the wave number, defined as \( k = \frac{2\pi}{\lambda} \) (where \( \lambda \) is the wavelength), - \( \omega \) is the angular frequency, defined as \( \omega = \frac{2\pi}{T} \) (where \( T \) is the time period of oscillation), - \( x \) is the position along the wave, - \( t \) is the time. Now, let's analyze the options provided: 1. **Option a:** \( y = A \sin(kx^2 - vt^2) \) This equation does not fit the standard wave equation form because it contains \( kx^2 \) and \( vt^2 \) instead of \( kx \) and \( \omega t \). Therefore, this is **not** a wave equation. 2. **Option b:** \( y = A \sin(kx - \omega t) \) This is the standard form of a wave equation. Hence, this is a wave equation. 3. **Option c:** \( y = A \sin\left(\frac{2\pi x}{\lambda} - \frac{2\pi t}{T}\right) \) This can be rewritten as \( y = A \sin(kx - \omega t) \) by substituting \( k = \frac{2\pi}{\lambda} \) and \( \omega = \frac{2\pi}{T} \). Therefore, this is also a wave equation. 4. **Option d:** \( y = A \sin(kx) \cos(\omega t) \) This represents a standing wave, which is formed by the superposition of two traveling waves. It can be derived from the wave equation and is still considered a wave equation. After analyzing all options, we conclude: - **Option a** is not a wave equation. - **Options b, c, and d** are wave equations. Thus, the correct answer is that option a is not a wave equation, while the others are.
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