Home
Class 12
PHYSICS
A compound micrscope consists of an obje...

A compound micrscope consists of an objective lens of focal length 1.0 cm and an eyepiece lens of focal length 5.0 cm separated by 12.2 cm At what distance from the objective lens should an object be placed to focus it properly so that the final image is formed at the least distance of clear vision (25cm)? b. calculate the angular magnificationn in this case.

Text Solution

Verified by Experts

For eyepiece, `V_(E) = 25 cm`., `f _(E)=+5 cm`
`rArr`  `U_(E)`= 4.17 cm = 4.2 cm
`L=v_(o) + |U_(E)| = 12.2 cm`, here `v_(O) = 8 cm`
  (a)`f_(O) = +1 cm`   `rArr`  `U_(o) = cap1.1 cm`
(b)`m=(V_(o))/(U_(o))[1+(D)/(f_(epsilon))]=((8)/(-1.1))[1+(25)/(5)]=-44`.
Promotional Banner

Similar Questions

Explore conceptually related problems

A compound microscope consists of an objects lens of focal length 2.0 cm and an eyepiece of focal length 20cm? If the system a converging or a diverging lens? Ignore thickness of the lenses.

A compound microscope consists of an objective lens of focal length 1 cm and an eye piece of focal length 5 cm with a separation of 10 cm. The distance between an object and the objective lens, at which the strain on the eye is minimum is n/40cm . The value of n is ___________

A compound microscope consists of an objective of focal length 1 cm and an eyepiece of focal length 5 cm. An object is placed at a distance of 0.5 cm from the objective. What should be the separation between the lenses so that the microscope projects an inverted real image of the object on a screen 30 cm behind the eyepiece?

A compound microscope consists of an objective lens with focal length 1.0 cm and eye piece of the focal length 2.0 cm and a tube 20 cm from eye lens. Now final image is formed at the near point of eye, so find the magnifying power of microscope.

A compound microscope uses an objective lens of focal length 4 cm and eye lens of focal length 10 cm . An object is placed at 6 cm from the objective lens. Calculate magnifying power of compound microscope if final image is formed at the near point. Also, calculate length of the tube of compound microscope.

A compound microscope has an objective of focal length 2.0 cm and an eye-piece of focal length 6.25cm and distance between the objective and eye-piece is 15cm . If the final image is formed at the least distance vision (25 cm) , the distance of the object form the objective is

A compound microscope has an eye piece of focal length 10 cm and an objective of focal length 4 cm . Calculate the magnification, if an object is kept at a distance of 5 cm from the objective so that final image is formed at the least distance vision (20 cm)

A convex lens of focal length 20 cm and a concave lens of focal length 10 cm are placed 20 cm apart. In between them an object placed at distance x from the convex lens. What is the value of x (in cm ) so that images from by both the lenses coincides ?

A compound microscope has an objective of focal length 1 cm and an eyepiece of focal length 2.5 cm. An object has to be placed at a distance of 1.2 cm away from the objective for normal adjustment. a.Find the angular magnification. b.Find the length of the microscope tube.

A diverging lens of focal length 20 cm and a converging mirror of focal length 10 cm are placed coaxially at a separation of 5 cm. Where should an object be placed so that a real image is formed at the object itself ?