Suppose that the electric field amplitude of an electromagnetic wave us `E_0=120 N// C` and that its frequency is `50.0 MHz`.
(a) Determine` B_0,omega,k` and `lambda`,
(b) find expressions for `E` and `B`.

Explanation

`B_(0)=(E_(0))/(c)=(120)/(3xx10^(8))=4xx10^(-7) T`
`omega = 2pi v = 3.14 xx 10^(8) rad//s`
`lambda=(C)/(V)=(3xx10^(8))/(5xx10^(7))=6m`
`k=(2pi)/(lambda)=1.05rad//m`
`E=E_(0)sin(kxomegat)`
=`120sin(1.05x-3.14xx10^(8)t)`
`B=B_(0)sin(kxomegat)`=`4xx10^(7)sin(1.05x-3.14t)`