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Parallel light of wavelength 5000 Å fall...

Parallel light of wavelength 5000 Å falls normally on a single slit. The central maximum spreads out to `30^(@)` on either side of the incident light.Find the width of the slit.For what width of the slit the central maximum would spread out to `90^(@)` from the direction of the incident light ?

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To solve the problem step by step, we will use the formula for single-slit diffraction. The formula relates the width of the slit (d), the wavelength of light (λ), and the angle of diffraction (θ). ### Step 1: Understand the given data - Wavelength (λ) = 5000 Å = 5000 × 10^(-10) m - Angle of spread for the central maximum (θ) = 30° on either side ### Step 2: Use the formula for single-slit diffraction The formula for the position of the first minimum in single-slit diffraction is given by: ...
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