In a plane electromagnetic wave, magnetic field oscillates with amplitude` 1.6 xx 10^(-11)T` Find the maximum value of electric field.

Answer

To find the maximum value of the electric field (E) in a plane electromagnetic wave when the magnetic field (B) oscillates with a given amplitude, we can use the relationship between the electric field and the magnetic field in electromagnetic waves.

### Step-by-Step Solution:

1. **Identify the given values**:
- The amplitude of the magnetic field (B) is given as:
\[ B = 1.6 \times 10^{-11} \, \text{T} \]

2. **Use the relationship between electric field and magnetic field**:
- In electromagnetic waves, the electric field (E) is related to the magnetic field (B) by the equation:
\[ E = c \cdot B \]
- where \( c \) is the speed of light in a vacuum, approximately:
\[ c = 3 \times 10^8 \, \text{m/s} \]

3. **Substitute the values into the equation**:
- Now, substitute the value of \( c \) and \( B \) into the equation:
\[ E = (3 \times 10^8 \, \text{m/s}) \cdot (1.6 \times 10^{-11} \, \text{T}) \]

4. **Calculate the electric field**:
- Perform the multiplication:
\[ E = 3 \times 1.6 \times 10^{8 - 11} = 4.8 \times 10^{-3} \, \text{V/m} \]

5. **Final result**:
- Therefore, the maximum value of the electric field is:
\[ E = 4.8 \times 10^{-3} \, \text{V/m} \]

### Summary:
The maximum value of the electric field in the electromagnetic wave is \( 4.8 \times 10^{-3} \, \text{V/m} \).

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