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The average value of electric energy den...

The average value of electric energy density in an electromagnetic wave is (`E_(0)` is peak value):

A

`(1)/(2)epsilon_(0)E^(2)`

B

`(E^(2))/(2epsilon_(0))`

C

`epsilon_(0)E^(2)`

D

`(1)/(4)epsilon_(0)E^(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the average value of electric energy density in an electromagnetic wave, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Electric Energy Density**: The electric energy density \( u \) in an electromagnetic wave is given by the formula: \[ u = \frac{1}{2} \epsilon_0 E_{\text{rms}}^2 \] where \( \epsilon_0 \) is the permittivity of free space and \( E_{\text{rms}} \) is the root mean square (rms) value of the electric field. 2. **Relating Peak Value to RMS Value**: The rms value of the electric field \( E_{\text{rms}} \) can be expressed in terms of the peak value \( E_0 \): \[ E_{\text{rms}} = \frac{E_0}{\sqrt{2}} \] 3. **Substituting RMS Value into Energy Density Formula**: Substitute the expression for \( E_{\text{rms}} \) into the energy density formula: \[ u = \frac{1}{2} \epsilon_0 \left( \frac{E_0}{\sqrt{2}} \right)^2 \] 4. **Calculating the Square**: Calculate the square of \( E_{\text{rms}} \): \[ \left( \frac{E_0}{\sqrt{2}} \right)^2 = \frac{E_0^2}{2} \] 5. **Final Expression for Energy Density**: Substitute this back into the energy density formula: \[ u = \frac{1}{2} \epsilon_0 \cdot \frac{E_0^2}{2} \] Simplifying this gives: \[ u = \frac{1}{4} \epsilon_0 E_0^2 \] 6. **Conclusion**: Thus, the average value of electric energy density in an electromagnetic wave is: \[ u = \frac{1}{4} \epsilon_0 E_0^2 \] ### Final Answer: The average value of electric energy density in an electromagnetic wave is \( \frac{1}{4} \epsilon_0 E_0^2 \). ---
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