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Find the aveage for the saw-tooth voltag...

Find the aveage for the saw-tooth voltage of peak value `V_(0)` from `t=0` to `t=2T` as shown in figure.

Text Solution

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As the equation of the Saw-tooth wave shown in the figure will be
`V=(2V_(@))/(T)t-V_(@)=V_(@)((2ty)/(T)-(1))`
`So,(a)V_av=(int_(0)^(T//2)(Vdt)/(int_(0)^(T//2)=(2)/(T)int_(@)^(T//2)V_(@)(2t)/(T)-1)dt=|V_(@)/(2)`
`and(b)V_(rms)[int_(@)^(T)V^(20dt)/(Int_(@)^(T)dt]]^(1//2)=(V_(@))/(sqrt3)`
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