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A sinusoidal voltage Vsin(at) is applied...

A sinusoidal voltage Vsin(at) is applied across a series combination of resistance R and inductor L. The amplitude of the current in the circuit is

A

`V_(0)/(sqrt(R^(2)+omega^(2)L^(2)))`

B

`(V_(0))/(sqrt(R^(2)-omega^(2)L^(2)))`

C

`(V_(0))/(sqrt(R^(2)+omega^(2)L^(2)))sinomegat`

D

VsqrtR`

Text Solution

AI Generated Solution

The correct Answer is:
To find the amplitude of the current in a circuit with a sinusoidal voltage applied across a series combination of resistance (R) and an inductor (L), we can follow these steps: ### Step 1: Identify the given parameters We have: - A sinusoidal voltage \( V(t) = V_0 \sin(\omega t) \) - Resistance \( R \) - Inductance \( L \) ### Step 2: Understand the concept of impedance In an R-L series circuit, the total impedance \( Z \) can be calculated using the formula: \[ Z = \sqrt{R^2 + X_L^2} \] where \( X_L \) is the inductive reactance. ### Step 3: Calculate the inductive reactance The inductive reactance \( X_L \) is given by: \[ X_L = \omega L \] where \( \omega \) is the angular frequency of the sinusoidal voltage. ### Step 4: Substitute \( X_L \) into the impedance formula Now substituting \( X_L \) into the impedance formula: \[ Z = \sqrt{R^2 + (\omega L)^2} \] ### Step 5: Calculate the amplitude of the current The amplitude of the current \( I_0 \) in the circuit can be calculated using Ohm's law for AC circuits: \[ I_0 = \frac{V_0}{Z} \] Substituting the expression for \( Z \): \[ I_0 = \frac{V_0}{\sqrt{R^2 + (\omega L)^2}} \] ### Final Answer Thus, the amplitude of the current in the circuit is: \[ I_0 = \frac{V_0}{\sqrt{R^2 + \omega^2 L^2}} \]

To find the amplitude of the current in a circuit with a sinusoidal voltage applied across a series combination of resistance (R) and an inductor (L), we can follow these steps: ### Step 1: Identify the given parameters We have: - A sinusoidal voltage \( V(t) = V_0 \sin(\omega t) \) - Resistance \( R \) - Inductance \( L \) ...
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