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An ideal choke takes a current of 8A whe...

An ideal choke takes a current of `8A` when connected to an a.c. source of `100` volt and `50Hz`. A pure resistor under the same conditions takes a current of `10A`. If two are connected in series to an `a.c.` supply of `100V` and `40Hz`, then the current in the series combination of above resistor and inductor is

A

10A

B

8A

C

5sqrt2 amp

D

10sqrt2 amp

Text Solution

Verified by Experts

The correct Answer is:
A
`X_(L)=(100)/(8),R=(100)/(10)=10Omega`
`Lxx100pi=(100)/(8)orL=(1)/(8pi)H`
`Z=sqrt(((1)/(8pi)xx2pixx40))^(2)+10=10sqrt2`
`I=(E)/(Z)=(100)/(10sqrt2)=(10)/sqrt2=5sqrt2A`
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