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In an L-C-R series resonant circuit, the...

In an L-C-R series resonant circuit, the capacitance is changed from C to 4C. For the same resonant frequency, the inductance should be changed from L to.

A

1//4

B

1//2

C

2L

D

4L

Text Solution

Verified by Experts

The correct Answer is:
A
`f=(1)/(2pi)sqrt((1)/(2))implies(1)/(L_(1)C_(1))=(1)/(L_(2)C_(2))`
`L_(2)=(L_(1)C_(1))/(C_(2))=(LxxC)/(4C)=(L)/(4)`
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