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If tangents are drawn to the ellipse x^2...

If tangents are drawn to the ellipse `x^2+2y^2=2,` then the locus of the midpoint of the intercept made by the tangents between the coordinate axes is (a) `1/(2x^2)+1/(4y^2)=1` (b) `1/(4x^2)+1/(2y^2)=1` (c) `(x^2)/2+y^2=1` (d) `(x^2)/4+(y^2)/2=1`

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The correct Answer is:
`(1)/(2x^(2))+(1)/(4y^(2))=1`
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