Home
Class 12
MATHS
A tangent to the ellipse Ax^(2)+9y^(2)=3...

A tangent to the ellipse `Ax^(2)+9y^(2)=36` is cut by the tangent at the extremities of the major axis at T and T`. The circle TT' as diameter passes through the point

A

`(-sqrt(5),0)`

B

`(sqrt(5),1)`

C

`(0,0)`

D

`(3,2)`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

A tangent to the ellipse 4x^2 +9y^2 =36 is cut by the tangent at the extremities of the major axis at T and T^1 , the circle on T T^1 as diameter passes through the point

The tangent at any point on the ellipse 16x^(2)+25y^(2) = 400 meets the tangents at the ends of the major axis at T_(1) and T_(2) . The circle on T_(1)T_(2) as diameter passes through

Prove that if any tangent to the ellipse is cut by the tangents at the endpoints of the major axis at Ta n dT ' , then the circle whose diameter is T T ' will pass through the foci of the ellipse.

The equation of tangent to the ellipse 2x^(2)+3y^(2)=6 which make an angle 30^(@) with the major axis is

The tangent at a point P on the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 , which in not an extremely of major axis meets a directrix at T. Statement-1: The circle on PT as diameter passes through the focus of the ellipse corresponding to the directrix on which T lies. Statement-2: Pt substends is a right angle at the focus of the ellipse corresponding to the directrix on which T lies.

The locus of the point of intersection of the tangents at the extermities of a chord of the circle x^2+y^2=b^2 which touches the circle x^2+y^2-2by=0 passes through the point

The tangents and normal at a point on (x^(2))/(a^(2))-(y^(2))/(b^(2)) =1 cut the y-axis A and B. Then the circle on AB as diameter passes through the focii of the hyperbola

The tagents at any point P of the circle x^(2)+y^(2)=16 meets the tangents at a fixed point A at T. Point is joined to B, the other end of the diameter, through, A. The sum of focal distance of any point on the curce is

The tangent to the curve y=xe^(x^2) passing through the point (1,e) also passes through the point

Prove that the perpendicular at the point of contact to the tangent to a circle passes through the centre.