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The point P on the ellipse 4x^2+9y^2=36 ...

The point P on the ellipse `4x^2+9y^2=36` is such that the are of the ` P F_1F_2=sqrt(10)` where `F_1,f_2` are foci. Then P has the coordinates
(a)`(3/(sqrt(2)),sqrt(2))` (b) `(3/2,2)` `(-3/2,-2)` (d) `(-3/(sqrt(2))-sqrt(2))`

A

`((3)/(sqrt(2)),sqrt(2))`

B

`((3)/(2),2)`

C

`((-3)/(2),-2)`

D

`((-3)/(sqrt(2)),- sqrt(2))`

Text Solution

Verified by Experts

The correct Answer is:
A, D
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