compute. `[(cosθ+isinθ)(cosθ−isinθ)]=?`

(cosθ-isinθ) ^ -n

The general value of the real angle θ, which satisfies the equation, (cosθ+isinθ)(cos 2 θ+isin2θ).(cosnθ+isinnθ)=1 is given by?

Compute cosec (13pi//12)

compute tan22(1^circ)/(2)

If cotθ+cosecθ=5 , find cosθ .

If 4sinθ+3cosθ=5 then tanθ=

[[Cosθ ,-Sinθ ],[Sinθ ,Sinθ ]]

Compute (98)^5 .

If a^2+b^2+c^2=1, then prove that |[a^2 +(b^2+c^2)cosθ, ab(1−cosθ), ac(1−cosθ)],[ba(1−cosθ),b^2(c^2+a^2)cosθ,bc(1−cosθ)],[ca(1−cosθ),cb(1−cosθ),c^2+(a^2+b^2)cosθ]| independent of a,b,c?

Prove that : (cosecθ−cotθ)^2 = (1+cosθ)/(1−cosθ) ​