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A bag contains 20 coins. If the probabil...

A bag contains 20 coins. If the probability that bag contains exactly 4 biased coin is `1//3` and that of exactly 5 biased coin is `2//3,` then the probability that all the biased coin are sorted out from the bag in exactly 10 draws is

A

`(5)/(33) (.^(16)C_(8))/(.^(20)C_(9))+(1)/(11)(.^(15)C_(5))/(.^(20)C_(9))`

B

`(2)/(33)[(2^(16)C_(6)+5^(15)C_(5))/(.^(20)C_(9))]`

C

`(5)/(33)(.^(16)C_(7))/(.^(20)C_(9))+(1)/(11)(.^(15)C_(6))/(.^(20)C_(9))`

D

none of these

Text Solution

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The correct Answer is:
B
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