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If two lines of Regression are respectiv...

If two lines of Regression are respectively y=ax+b and x=`alphay+beta.` If the two variables have the same mean, then `b//beta`=

A

`(1+a)/(1+alpha)`

B

`(1+alpha)/(1+a)`

C

`(1-a)/(1-alpha)`

D

`(1-alpha)/(1-a)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the two regression equations given and derive the relationship between \( b \) and \( \beta \) under the condition that the means of the two variables are equal. ### Step-by-Step Solution: 1. **Understanding the Regression Equations**: We have two regression equations: \[ y = ax + b \quad \text{(1)} \] \[ x = \alpha y + \beta \quad \text{(2)} \] 2. **Setting the Means Equal**: Given that the two variables have the same mean, we denote the means as \( x̄ \) and \( ȳ \). Therefore, we can set: \[ x̄ = ȳ \] 3. **Substituting Means into the Equations**: From equation (1), substituting \( x = y = x̄ \): \[ ȳ = ax̄ + b \] Since \( x̄ = ȳ \), we can rewrite this as: \[ x̄ = ax̄ + b \quad \text{(3)} \] 4. **Rearranging Equation (3)**: Rearranging equation (3) gives: \[ x̄ - ax̄ = b \] Factoring out \( x̄ \): \[ x̄(1 - a) = b \] Thus, we can express \( x̄ \) as: \[ x̄ = \frac{b}{1 - a} \quad \text{(4)} \] 5. **Substituting Back into the Second Equation**: Now, substitute \( ȳ = x̄ \) into equation (2): \[ x̄ = \alpha ȳ + \beta \] Replacing \( ȳ \) with \( x̄ \): \[ x̄ = \alpha x̄ + \beta \] 6. **Rearranging this Equation**: Rearranging gives: \[ x̄ - \alpha x̄ = \beta \] Factoring out \( x̄ \): \[ x̄(1 - \alpha) = \beta \] Thus, we can express \( x̄ \) as: \[ x̄ = \frac{\beta}{1 - \alpha} \quad \text{(5)} \] 7. **Equating the Two Expressions for \( x̄ \)**: From equations (4) and (5), we have: \[ \frac{b}{1 - a} = \frac{\beta}{1 - \alpha} \] 8. **Cross-Multiplying**: Cross-multiplying gives: \[ b(1 - \alpha) = \beta(1 - a) \] 9. **Finding the Ratio \( \frac{b}{\beta} \)**: Rearranging the above equation leads to: \[ \frac{b}{\beta} = \frac{1 - a}{1 - \alpha} \] ### Final Result: Thus, the final result is: \[ \frac{b}{\beta} = \frac{1 - a}{1 - \alpha} \]
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