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For A+B hArr C, the equilibrium concentr...

For `A+B hArr C`, the equilibrium concentration of A and B at a temperature are `15 mol L^(-1)`. When volume is doubled the reaction has equilibrium concentration of A as `10 mol L^(-1)`, calculate
a. `K_(c)`

Text Solution

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`{:("",A,+B,hArrC,""),("At eqm. (i) conc",15,15,a,("volume in V litre")),("When V.double conc",(15)/2,(15)/2,a/2,("Volume in 2V litre")):}`
Since, on increasing volume pressure decreases and the reaction proceeds in the direction where it shows an increase in number of mole ,i.e beckward reaction.
`{:("",A,+B,hArr,C),("At eqm.(ii) conc.",((15)/2+x),((15)/2+x),"",(a/2-x)):}`
`because ((15)/2+X)=10,x=5/2`
`K_c=([C])/([A][B])=([a/2-5/2])/([(15)/2+5/2][(15)/2+5/2])` ........(1) For eqm. II
Also, `([C])/([A][B])=a/(15xx15)` .........(2) For eqm . I
`because K_c` are same
`((a-5)//2)/(10xx10)=a/(15xx15) thereforea= 45 M`
`K_c =(45)/(15xx15)=0.2 mol^(-1)L^(-1)`
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