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When limestone is heated, quick lime is ...

When limestone is heated, quick lime is formed according to the equation,
`CaCO_3 (s) hArr CaO(s) +CO_2 (g)`
The experiment was carried out in the temperature range `800 -900 ^@C` . Equilibrium constant `K_p` follows the relation, `log_(10) K_p=7.282-8500//T` where T is temperature in kelvin . At what temperature the decomposition will give `CO_2(g)` at 1 atm ?

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AI Generated Solution

To solve the problem, we will follow these steps: ### Step 1: Understand the Reaction and Given Information The reaction given is: \[ \text{CaCO}_3 (s) \rightleftharpoons \text{CaO} (s) + \text{CO}_2 (g) \] We need to find the temperature at which the equilibrium constant \( K_p \) will allow the decomposition of calcium carbonate to produce \( CO_2 \) gas at a pressure of 1 atm. ...
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