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One mole of N(2)O(4)(g) at 300 K is kept...

One mole of `N_(2)O_(4)(g)` at 300 K is kept in a closed container under one atmosphere. It is heated to 600K when 20% by mass of `N_(2)O_(4)`(g) decomposes to `NO_(2)`(g). The resultant pressure is:

A

0.1

B

0.2

C

0.3

D

0.4

Text Solution

Verified by Experts

The correct Answer is:
B
`N_2O_4(g) hArr2NO_2(g)`
Equilibrium `1-alpha 2alpha`
Where `alpha ` is the degree of dissociation = `(600)/(300)`
`(because` V is constant)
`therefore P_2=2 atm`
After dissociation of `N_2O_4` at 600 k,
`P_(N_2O_4=2(1-alpha)`
`=2-2alpha`
`P_(N_2O_4=2xx2alpha`
`=4alpha`
Total pressure `=2-2alpha+4alpha`
`=2+2alpha`
`2+2alpha=2.4`(Given)
`alpha=0.2`
`therefore` Percentage dissociation = 20% .
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