Home
Class 12
CHEMISTRY
When NaNO(3)(s) is heated in a closed ve...

When `NaNO_(3)(s)` is heated in a closed vessel, oxygen is liberated and `NaNO_(2)(s)` is left behind. At equilibrium,

A

addition of `NaNO_2` favours reverse reaction

B

addition of `NaNO_3` favours forward reaction

C

increasing temperature favours forward reaction

D

increasing pressure favours reverse reaction

Text Solution

Verified by Experts

The correct Answer is:
C, D
`2NaNO_3 (s) hArr 2NaNO_2(s) +O_2(g)`
Applying law of chemical equilibrium `k=[O_2(g)]`. Hence addition of `NaNO_2` or `NaNO_3` will not distturb the equilibrium i.e (A) and (B) are wrong . Only (C ) and (D) are correct.
Promotional Banner

Similar Questions

Explore conceptually related problems

When NaNO_(3) is heated in a closed vessel, oxygen is liberated and NaNO_(2) is left behind. At equilibrium, which are correct

When NaNO_(3) is heated in a closed vessel, oxygen is liberated and NaNO_(2) is left behind. At equilibrium

NaNO_(3) on heating gives

Nitrogen is obtained when NaNO_2 reacts with

On heating NaNO_(3) gives:

Two moles of PCl_(5) is heated in a closed vessel of 2 L capacity. When the equilibrium is attained 40 % of it has been found to be dissociated. What is the Kc in mol//dm^(3) ?

NaNO_(3) on heating with sodium hydroxide solution and zinc liberates a gas which is also obtained by :

2 "mole" of PCl_(5) were heated in a closed vessel of 2 litre capacity. At equilibrium 40% of PCl_(5) dissociated into PCl_(3) and Cl_(2) . The value of the equilibrium constant is:

2 "mole" of PCl_(5) were heated in a closed vessel of 2 litre capacity. At equilibrium 40% of PCl_(5) dissociated into PCl_(3) and Cl_(2) . The value of the equilibrium constant is:

Suppose the reaction PC1_(5(s))hArrPC1_(3(s)) + C1_(2(g)) is in a closed vessel at equilibrium stage. What is the effect on equilibrium concentration of C1_(2(g)) by adding PCl_(5) at constant temperature ?