What is the concentration of CO in equilibrium at `25^(@)C` in a sample of a gas originally containing 1.0 mol `L^(-1)` of `CO_(2)` ? For dissociation of `CO_(2)` at `25^(@)C, K_(c)=2.96xx10^(-92)`.

Degree of dissociation of 0.1 molar acetic acid at 25^(@)C (K_(a) = 1.0 xx 10^(-5)) is

What is the density of CO_(2) at 27 .^(@)C and 2.5 atm pressure ?

What concentration of CO_(2) be in equilibrium with 2.5xx10^(-2) mol L^(-1) of CO at 100^(@)C for the reaction: FeO(s)+CO(g) hArr Fe(s)+CO_(2)(g), K_(c)=5.0

What concentration of CO_(2) be in equilibrium with 0.025 M CO at 120^(@)C for the reaction FeO(s)+CO(g) hArr Fe(s)+CO_(2)(g) if the value of K_(c)=5.0 ?

If a closed container contain 5 moles of CO_(2) gas, then find total number of CO_(2) molecules in the container (N_(A)=6xx10^(23))

Calculate the concentration of CO_(2) in a soft drink that is bottled with a partial pressure of CO_(2) of 4 atm over the liquid at 25^(@)C . The Henry's law constant for CO_(2) in water at 25^(@)C is 3.1 xx 10^(-2) "mol/litre-atm" .

The density of a sample of SO_(3) gas is 2.5 g/L at 0^(@) C and 1 atm . It's degree of dissociation into SO_(2) and O_(2) gases is :

An equilibrium mixture CO(g)+H_(2)O(g) hArr CO_(2)(g)+H_(2)(g) present in a vessel of one litre capacity at 815^(@)C was found by analysis to contain 0.4 mol of CO, 0.3 mol of H_(2)O, 0.2 mol of CO_(2) and 0.6 mol of H_(2) . a. Calculate K_(c) b. If it is derived to increase the concentration of CO to 0.6 mol by adding CO_(2) to the vessel, how many moles must be addes into equilibrium mixture at constant temperature in order to get this change?

At 448^(@)C , the equilibrium constant (K_(c)) for the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) is 50.5 . Predict the direction in which the reaction will proceed to reach equilibrium at 448^(@)C , if we start with 2.0xx10^(-2) mol of HI, 1.0xx10^(-2) mol of H_(2) and 3.0xx10^(-2) mol of I_(2) in a 2.0 L container.

The concentration of CO_(2) in atmosphere is 88ppm. If all of the CO_(2) present in 10^(5)mL of air is dissolved in 1dm^(3) water, then approximate pOH of solution at 27^(@)C will be (K_(a_(1)) = 10^(-7), K_(a_(2)) = 10^(-11) for H_(2)CO_(3)]