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At 1000K, the pressure of iodine gas is ...

At 1000K, the pressure of iodine gas is found to be 0.112 atm due to partial dissociation of `I_(2)(g)` into I(g). Had there been no dissociation, the pressure would have been 0.074 atm. Calculate the value of `K_(p)` for the reaction:
`I_(2)(g) hArr 2I(g)`.

Text Solution

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`K_p =0.16 atm`
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