Home
Class 12
CHEMISTRY
At 1000^@C the pressure of iodine gas i...

At `1000^@C` the pressure of iodine gas is found to be 0.112 atm whereas the expected pressure is 0.074 atm. The increased pressure is due to dissociation, `I_2 hArr 2I`. Calculate `K_p` . Also find out pressure at which `I_2` will be 90% dissociation at `1000^@C`.

Text Solution

AI Generated Solution

To solve the problem, we will follow these steps: ### Step 1: Understand the Reaction The dissociation of iodine gas can be represented as: \[ I_2 \rightleftharpoons 2I \] ### Step 2: Set Up Initial Conditions At the start (t = 0): ...
Promotional Banner

Similar Questions

Explore conceptually related problems

The pressure of iodine gas at 1273 K is found to be 0.112 atm whereas the expected pressure is 0.074 atm. The increased pressure is due to dissociation I_(2) hArr 2I . Calculate K_(p) .

The degree of dissociation of PCl_(5) at 1 atm pressure is 0.2 . Calculate the pressure at which PCl_(5) is dissociated to 50% ?

The pressure of a gas is 2.5 atm . Calculate the value in torr.

At some temperature and under a pressure of 4 atm, PCl_(5) is 10% dissociated. Calculated the pressure at which PCl_(5) will be 20% dissociated temperature remaining same.

At 1000K, the pressure of iodine gas is found to be 0.112 atm due to partial dissociation of I_(2)(g) into I(g). Had there been no dissociation, the pressure would have been 0.074 atm. Calculate the value of K_(p) for the reaction: I_(2)(g) hArr 2I(g) .

At 1000K , the pressure of iodine gas is found to be 0.1 atm due to partial dissociation of I_(2)(g) into I(g) . Had there been no dissociation, the pressure would have been 0.07 atm . Calculate the value of K_(p) for the reaction: I_(2)(g)hArr2I(g) .

A certain temperature, the degree of dissociationof PCI_(3) was found to be 0.25 under a total pressure of 15 atm. The value of K_(p) for the dissociation of PCl_(5) is

At 27^(@)C and 2.0 atm pressure, the density of propene gas is :

Calculate the volume percent of chlorine gas at equilibrium in the dissociation of PCl_(5)(g) under a total pressure of 1.5 atm. The K_(p) for its dissociation =0.3 .

A certain sample of gas has a volume of 0.2 litre measured at 1 atm pressure and 0^(@)C . At the same pressure but at 273^(@)C , its volume will be