The dissociation of `PCl_5` decreases in presence of `Cl_2` Why ?

Dissociation of NH_(4)OH is decreased in presence of :-

The degree of dissociation of PCl_(5) decreases with increase in pressure.

The volume percentage of Cl_2 at equilibrium in the dissociation of PCl_5 under a total pressure of 1.5atm is (Kp = 0.202) ,

Phosphorus pentachloride dissociates as follows in a closed reaction vessel PCl_5 (g) hArr PCl_3 (g) + Cl_2( g) If total pressure at equilibrium of the reaction mixture is P and degree of dissociation of PCl_5 is x, the partial pressure of PCl_3 will be.

Assertion : In the dissociation of PCl_(5) at constant pressure and temperature addition of helium at equilibrium increases the dissociation of PCl_(5) . Reason : Helium reacts with Cl_(2) and hence shifts the equilibrium in forward direction.

The degree of dissociation of PCl_(5) at 1 atm pressure is 0.2 . Calculate the pressure at which PCl_(5) is dissociated to 50% ?

Assertion :- Adding inert gas at equilibrium to dissociation of PCl_(5) at constant pressure increases the degree of dissociation. Reason :- Since degree of dissociation x alphasqrt(v)

Four moles of PCl_(5) are heated in a closed 4 dm^(3) container to reach equilibrium at 400 K. At equilibrium 50% of PCl_(5) is dissociated. What is the value of K_(c) for the dissociation of PCl_(5) into PCl_(3) "and" Cl_(2) at 400 K ?

For the dissociation of PCl_(5) into PCl_(3) and Cl_(2) in gaseous phase reaction , if d is the observed vapour density and D the theoretical vapour density with 'alpha' as degree of dissociation ,variaton of D/d with 'alpha' is given by ?

The degree of dissociation of PCl_(5) will be more at ………. pressure.