When the system `2HI(g) hArr H_(2)(g)+I_(2)(g)` is at equilibrium, inert gas is introduced. Dissociation of `HI` is ………….

For the reaction, 2HI(g) rarr H_(2)(g) + I_(2) (g) - Q KJ , the equilibrium constant depends upon

In the reversible reaction, 2HI(g) hArr H_(2)(g)+I_(2)(g), K_(p) is

In an experiment 5 moles of HI were enclosed in a 5 litre container . At 717 K equilibrium constant for the gaseous reaction , 2HI (g) hArr H_2(g) +I_2(g) is 0.025 . Calculate the equilibrium concentration of HI ,H_2 and I_2 . What is the fraction of HI that decomposes ?

For 2HI(g) hArr H_2(g)+I_2(g) write the expression of k_c .

To the system H_(2)(g)+I_(2)(g) hArr 2HI(g) in equilibrium, some N_(2) gas was added at constant volume. Then,

Addition of inert gas to system N_(2)(g) + 3H_(2)(g) at equillibrium at constant volume. Then

At a certain temperature , only 50% HI is dissociated at equilibrium in the following reaction: 2HI(g)hArrH_(2)(g)+I_(2)(g) the equilibrium constant for this reaction is:

If the equilibrium constant of the reaction 2HI(g)hArrH_(2)(g)+I_(2)(g) is 0.25 , find the equilibrium constant of the reaction. (1)/(2)H_(2)+(1)/(2)I_(2)hArrHI(g)

In the equilibrium reaction, 2HI(g)hArr H_(2)(g)+I_(2)(g) , which of the following expressions is true?

8 mol of gas AB_(3) are introduced into a 1.0 dm^(3) vessel. It dissociates as 2AB_(3)(g) hArr A_(2)(g)+3B_(2)(g) At equilibrium, 2 mol of A_(2) is found to be present. The equilibrium constant for the reaction is