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The equilibrium constant for the reactio...

The equilibrium constant for the reaction `N_2(g) +O_2(g) hArr 2NO(g) "is" 4 xx 10^(-4)` at 200 k . In the presence of a catalyst the equilibrium is attained 10 times faster therefore, the equillbrium constant in presence of the catalyst at 200 k is

A

`4 xx 10^(-3)`

B

`4xx 10^(-4)`

C

`4xx 10^(-5)`

D

none

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The correct Answer is:
To solve the problem, we need to understand the concept of the equilibrium constant and how it is affected by various factors. ### Step-by-Step Solution: 1. **Identify the given information:** - The equilibrium constant \( K \) for the reaction \( N_2(g) + O_2(g) \rightleftharpoons 2NO(g) \) is given as \( 4 \times 10^{-4} \) at a temperature of 200 K. - A catalyst is used which speeds up the attainment of equilibrium by 10 times. 2. **Understand the role of a catalyst:** - A catalyst increases the rate of both the forward and reverse reactions equally, allowing the system to reach equilibrium faster. - However, it does not change the position of equilibrium or the value of the equilibrium constant. 3. **Determine the effect of the catalyst on the equilibrium constant:** - The equilibrium constant \( K \) is a function of temperature only. It does not depend on the presence of a catalyst or the speed at which equilibrium is reached. - Therefore, the equilibrium constant remains the same regardless of whether a catalyst is present or not. 4. **Conclude the value of the equilibrium constant in the presence of the catalyst:** - Since the catalyst does not affect the equilibrium constant, the equilibrium constant in the presence of the catalyst at 200 K is still \( 4 \times 10^{-4} \). ### Final Answer: The equilibrium constant in the presence of the catalyst at 200 K is \( 4 \times 10^{-4} \). ---
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