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Calculate the volume of oxygen required ...

Calculate the volume of oxygen required for the complete combustion of 8.8 g of propane (`C_3H_8`). (Atomic mass : C = 14, O = 16, H = 1, Molar Volume = 22.4 `dm^3` at S.T.P).

Text Solution

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`{:(2KClO_(s)(s),to,2KCl(s) + 3O_(2)(g)),(2xx 122.5 kg,," "2xx 32 kg):}`
Mass of `O_(2)` obtained by 10 kg of `KClO_(3) = (96 xx 10)/245 = 3.92 kg`
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