Find out the volume of `Cl_(2)` at STP produced by the action of 100 `cm^(3)` of `0.2N` HCl on excess of `MnO_(2)`.

Explanation

To find the volume of Cl₂ produced at STP from the reaction of 100 cm³ of 0.2N HCl with excess MnO₂, we can follow these steps:

### Step 1: Write the balanced chemical equation
The reaction between MnO₂ and HCl can be represented as:
\[ \text{MnO}_2 + 4\text{HCl} \rightarrow \text{MnCl}_2 + 2\text{Cl}_2 + 2\text{H}_2\text{O} \]

From the balanced equation, we can see that 4 moles of HCl produce 1 mole of Cl₂.

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