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25 mL of N/10 NaOH solution exactly neu...

25 mL of `N/10 NaOH` solution exactly neutralise 20 mL of an acid solution. What is the normality of the acid solution ?

Text Solution

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`N_(1)V_(1) = N_(2)V_(2)`
(NaOH) (Acid)
` 1/10 xx 25 = N_(2) xx 20`
` N_(2) = 25/(10 xx 20) = 0.125`
Strength = Normality `xx` Eq.mass
Eq. mass of the acid = `(7.875)/(0.125)`
` = 63.00`
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